10 tricks for interfacing to the PIC16C5 | Schematic Diagrams

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10 tricks for interfacing to the PIC16C5


Most of the ideas in this chapter can be found on the
pages of this website, but just in case you want to go over the
capabilities of the `508A, we have brought them together.

Quite often when you are programming, the first thing you will
run out of is output lines. Many projects need lots of drive
lines and if you need more than about 8, you should go to another

Don`t expect an 8-pin chip to perform the impossible.

The designers of the `508A have done an amazing job providing 5
output lines (and one input line) in an 8-pin chip, but even so,
many projects run out of drive-lines.

On other pages of this course we have shown how to expand the
drive lines with a binary counter or shift register. This can
increase the lines to more than 10 however if you want to add
just one or tw1o more devices than the chip is directly capable
of handling (5), there are clever ways to connect them to
the chip.


One of the simplest combinations is a LED and Piezo on a
single drive-line as shown in fig: 1. These can be combined
because the requirements of a LED are different to a piezo. A LED
requires a constant HIGH for it to illuminate while a piezo
requires a HIGH-LOW-HIGH waveform at approx 3kHz to produce a

10 20Tricks fig1 10 tricks for interfacing to the PIC16C5

If the mark-space ratio of this waveform is kept short as
shown in fig: 2, the LED will only illuminate very dimly. A short
mark-space ratio means the “mark” is very small compared to the
“space”. A very
short on-time (mark) and a long
off-time (space) will not affect the tone from the piezo but will
deliver very little energy to the LED and this is exactly what
we want.

10 20Tricks fig2 10 tricks for interfacing to the PIC16C5

On the other hand, each time the LED is activated, only a very
small click will be heard, and this will hardly be noticeable.
In this way the tw1o devices can be combined on the same line.


In this book, we show how to connect tw1o and up to five or
more push buttons on a single input line and generally you will
not have any problems adding buttons to a project. But if you
want to add a secret reset button (or a “cheat” button, for
example), it can be added across an existing LED as shown in fig:

10 20Tricks fig3 10 tricks for interfacing to the PIC16C5

The resistor betw1een the switch and micro acts as a safety
resistor to prevent the output of the chip being damaged if the
switch is pressed when the LED is activated, and it also acts as a
dropper resistor for the LED.

These tw1o items will work in combination because the
impedance of the LED is very high when no voltage is across it
and when the micro turns the line into an input line, it sees the
LED as a high impedance. In other words it is not detected so
that when the switch is pressed the micro only sees the switch as
a LOW.


Up to 5 different programs can be burnt into a single `508A
and the required program can be accessed by soldering a resistor
betw1een one of the outputs and the “input-only” line – GP3, as
shown in fig: 4.

10 20Tricks fig4 10 tricks for interfacing to the PIC16C5

During turn-on, a special program will put a HIGH on each
output in turn and the output containing the resistor will
determine the program.

Combining 5 programs in one chip will reduce inventory costs
as the required program can be selected by fitting the resistor
in the appropriate place on the board.


If a device is connected betw1een tw1o output lines as shown
in fig: 5, a program can be written so that the device sees a
voltage reversal. When one output is HIGH the other is LOW and
this is then reversed.

10 20Tricks fig5 10 tricks for interfacing to the PIC16C5

The drive lines have a maximum output current of 25mA and this
is enough to drive a number of different devices. If a red LED
is connected in one direction and a green LED in the opposite
direction, they can be turned on and off individually, as shown
in fig: 6.

10 20Tricks fig6 10 tricks for interfacing to the PIC16C5

If the tw1o LEDs are placed near each other or combined in the
one LED (called a tri-coloured LED), they will produce a number
of colours including orange, depending on the mark-space waveform
delivered to each LED.

A single LED containing red and green chips is available in 2
or 3 lead versions. The wiring for a 3-leaded tri-colour LED is
shown in fig: 7. The tri-leaded version is shown in fig: 6.

10 20Tricks fig7 10 tricks for interfacing to the PIC16C5

Tri-coloured LEDs are fairly expensive but if the project can
cover the expense, they can be the basis of “running message”
displays and simple TV screens.

If you connect a piezo to tw1o out-of-phase lines as shown in
fig: 8b, the sound produced will be slightly louder than the
arrangement in fig: 8a.

10 20Tricks fig8 10 tricks for interfacing to the PIC16C5

When we talk about a piezo we really mean a PIEZO DIAPHRAGM. A
piezo diaphragm is a passive device and is very similar to a
capacitor as far as the circuit is concerned. Ceramic substrate
on a metal diaphragm causes the metal to “dish” and bend to
produce a high pitched sound. The size of the voltage (the
amplitude) determines the intensity of the sound and the
frequency of the waveform determines the tone.

The voltage across the piezo from one drive line is about 5v
whereas the voltage seen by the piezo from tw1o reversing lines
is about 10v. Unfortunately this doesn`t produce tw1ice the sound
output but the sound is slightly louder. If you want a
louder output you should use a better-quality high-output
diaphragm (such as from a Christmas card).

The loudest output is a piezo siren and this is an active
device containing a transistor oscillator and choke. These units
operate from 5v to 15v and produce a very loud output while
consuming only about 10mA to 15mA.


Each output line of a `508A can only deliver about 25mA. This
current is determined by the size of the transistor delivering
the current. The transistor inside the chip is only very tiny and
if a higher current
is drawn, it may be damaged.

10 20Tricks fig9 10 tricks for interfacing to the PIC16C5

When a resistance of 200 ohms is connected from output to
ground, a current of 25mA flows (when the output is HIGH). If the
resistance is reduced, a higher current flows. This means a
resistance of 200 ohms or higher is required to make sure the
current flow is less than 25mA.

But if a LED is placed on the output, how is the resistance worked out?

A LED drops a voltage across it according to its colour. This
is called the CHARACTERISTIC voltage or the CHARACTERISTIC
VOLTAGE DROP. This voltage is constant, no matter how bright the
LED is illuminated.

For a red LED the characteristic voltage is 1.7v.

For an orange LED the characteristic voltage is 1.9v.

For a green LED the characteristic voltage is 2.1v.

LEDs cannot be connected directly to the output of a drive-line without a voltage-dropping resistor.

The reason is very technical but basically a red LED does not
turn on AT ALL until exactly 1.7v is placed across it and if the
voltage tries to rise above 1.7v, the LED will glow brighter,
allow a very high current to flow and will be damaged.

The only way to prevent damaging the LED is to provide it with
a very accurate supply voltage or simply connect a resistor in
series. If the value of the resistance is worked out, an accurate
current can be delivered to the LED and everything will be ok.
The LED will last 100 years!

Suppose you want to deliver 25mA to a LED.

If we take a red LED, the value of resistance can be worked
out by Ohms law. The voltage across the resistor is: 5v – 1.7v =

I = V/R

0.025 = 3.3/R

R = 132 ohms Use 130R resistor.


If a number of LEDs are required to be driven from a single
output, you will need to connect them in parallel or series.
There are limitations, however, as you will see.

Firstly it is ok to connect tw1o LEDs in series, provided you work out the value of the dropper resistor.

If a single red LED is connected to an output and supplied
with 25mA via a 130 ohm resistor, when tw1o LEDs are connected in
series, the second LED will drop 1.7v and the supply voltage
will be 5v – 3.4v = 1.6v. In this case the tw1o LEDs will receive
a current of 12mA from the 130 ohm resistor and they may be a
lot duller than expected.

To supply them with 25mA, the dropper resistor must be:

R = V/I

= 1.6/0.025

= 64 ohms

Use 68R resistor as shown in fig: 10.

10 20Tricks fig10 10 tricks for interfacing to the PIC16C5

If three LEDs are connected in series, the total
characteristic voltage drop will be 1.7v + 1.7v + 1.7v = 5.1v
This is higher than the maximum voltage on the output line and in
theory, the LEDs will not illuminate AT ALL, no matter what
dropper resistor is used!

This means only tw1o LEDs can be connected in series to an output line.

LEDs can be connected in parallel AND series as shown in fig:
11. Four LEDs is the maximum that can be driven from a single
output line and this will deliver about 12mA to each LED.

10 20Tricks fig11 10 tricks for interfacing to the PIC16C5

You will notice a separate dropper resistor is required for
each column of LEDs because LEDs cannot be operated in parallel
due to the 1.7v characteristic voltage required across each for
perfect operation.

For example: one LED may have a characteristic of 1.75v and
another may have 1.65v characteristic. The 1.65v LED will rob the
other of voltage and prevent it operating. More on this in our
Notebook series.


If more than 4 LEDs are required to be driven, a buffer
transistor will be required as shown in fig: 12. This transistor
will allow the LEDs to be driven from a 12v supply (or higher)
and the number of LEDs can be increased to 6 per column for 12v.

10 20Tricks fig12 10 tricks for interfacing to the PIC16C5

If the transistor can handle 100mA, four columns can be made, allowing 24 LEDs to be illuminated.

In this way segments of a large pattern can be illuminated and
by referring to some of the projects we have included, the lines
of the `508A can be expanded to tw1elve or more and an
impressive display can be created.


A globe is a device that requires a very high start-up
current. This is something you may not be aware of. The start-up
or warm-up current for a globe is about 6 times its operating
current and although this current is drawn for only a very short
period of time, it is one of the reasons why a globe does not
work in some circuits. The high start-up current prevented one
of our flip-flop circuits working. The resistance of the
leads from the project to the battery was sufficient to prevent
the circuit starting-up. That`s why it is important to remember
everything we discuss.

To drive a globe from an output of the microcontroller, a buffer transistor is needed.

Any type of transistor will be suitable providing its current
handling ability is about 600mA for each 100mA of operating
current for the globe. A suitable drive circuit is shown in fig:

10 20Tricks fig13 10 tricks for interfacing to the PIC16C5

The globe can be dimmed by delivering a variable mark-space
waveform. Fig:2 shows the type of waveform with the on-time
represented by the “mark” portion of the waveform.


Most relays require more than 25mA for operation and need a 12v supply.

For this a buffer transistor is required. Fig: 14 shows how a
relay is connected to an output of the `508A. The diode across
the relay prevents voltage from the relay getting into any of the
supply lines and affecting the operation of the microprocessor.

10 20Tricks fig14 10 tricks for interfacing to the PIC16C5

When the relay is turned off (de-energised) the collapsing
magnetic field of the coil generates a very high voltage and this
can be passed to the supply rail if it is not “snubbed.” The
diode absorbs (snubs) this voltage.


When designing an alarm project, the wiring betw1een the
sensors and the control panel must not be able to be cut
otherwise the alarm system is useless!

Making the wiring FULLY SECURE is very complex but a simple
way to prevent the wires being cut or joined together (without
detection) involves a line-sensing feature called LINE REVERSAL.

Most alarms consist of pin switches or reed switches with the
windows and doors physically keeping the switch closed or having a
magnet to keep the contacts of a reed-switch closed. If the door
or window is opened, the circuit becomes open and the alarm is

This is called a CLOSED LOOP detection circuit.

It`s very easy to see that if the tw1o wires going to the
alarm panel are joined together near the alarm panel, the alarm
will not activate when a window or door is opened.

To overcome this problem a diode is placed in the line near one of the sensors as shown in fig: 15.

10 20Tricks fig15 10 tricks for interfacing to the PIC16C5

The alarm is required to send out a HIGH on one line and
detect the high on the other line. The alarm then sends out a
HIGH on the other line and since the diode is reverse biased for
this condition, the
alarm must sense a low on the first line.

This “line testing” is done many times per second and if the
line is shorted, the program will detect the interference. The
only limitation to this system is the micro will not detect a
diode fitted across the tw1o lines near the alarm panel. The
thief has to know of this limitation and the diode has to be
fitted around the correct way to defeat the system.

How many thieves carry a diode with them and know how to fit it?


In theory you can connect a motor to tw1o drive-lines and get forward and reverse operation.

But unfortunately a motor requires a very high start-up
current and the drive lines of a `508A are not capable of
delivering this current. The solution is to use transistor
buffers in the bridge arrangement
of fig: 16.

10 20Tricks fig16 10 tricks for interfacing to the PIC16C5

Lines A and B are tw1o outputs from a `508A. There is an
important point to remember when programming the output lines to
prevent a short-circuit occurring with the bridge.

You will notice that if both A and B are HIGH at the same
time, transistors L, M and X, Y will be turned on at the same
time and a short-circuit will occur on the power rail.

To prevent this from happening lines A and B must be LOW at the beginning of the program.

By taking line A HIGH, transistors M and X are turned on and
this delivers voltage to the motor to turn it in the clockwise

To control the RPM of the motor, line A can be given a variable mark-space ratio.

To reverse the motor, line A must be taken low and after a
short delay, line B can be taken HIGH. This will deliver voltage
to the motor via transistors Y and L and cause the motor to
revolve in the opposite direction. Reverse RPM can be adjusted
with a variable mark-space pulse.

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