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10 minute time delay by fet 2N3819
This circuit is a basic function of the FET 2N3819, which acts as a switch. In the conduction and not conduction. It runs contrary to the transistor. The circuit can be used to delay the cycle is small. Such as delay, 9-volt light bulb, or motor delay to any DC 9 volts.
When raising the power supply circuit FET Q1 is running. D and S stand by the legs of furniture to the Tong Q1 will flow together, current flows through R2, so the flow from the legs through the leg and S. D, and through R4 to ground. So no current flows into R3 to transistor Q2 does not conduct. Resulting in a voltage appearing at the output is 12 volt, but when I press the S1 switch current flows into the capacitor C1 fully. Then go to the legs G of the FET. Q1 stopped working. Therefore, the current flowing through R2 is flowing to the R3 instead, and to bias transistor Q2 to work on the output transistor Q2 is not working out for 10 minute, because C1 is discharged. The S2 is the reset switch. By acting shock C1 to discharge out soon. That the time delay depends on the C1. If it will delay much longer, if less it will have less delay.
If you basic timer with FET, see below.
Basic Timer using FET 2N3819
This circuit be Basic Timer Circuit by use important equipment is FET 2N3819. By this circuit can can delay long ago arrive at 1.5 minute. Stand S1 at a position Reset an electric bell will loud. Totter S1 come back at time an electric bell will silent until time drag will stop electric bell talk at one time again. If friends enhance the value C1 or R1 for delay long ago go up. devalue R2 while stay in a position Reset for Reset fast go up. Request friends have fun Basic Timer Circuit , please sir.
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